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Question

Chemistry Question on Electrochemistry

What will be the emf of the following concentration cell at 25C25^{\circ}C? Ag(s)AgNO3(0.01M)AgNO3(0.05M)Ag(s)Ag_{\left(s\right)}\left|AgNO_{3}\left(0.01\,M\right)\right|\left|AgNO_{3}\left(0.05\,M\right)\right|Ag_{\left(s\right)}

A

0.828V0.828\,V

B

0.0413V0.0413\, V

C

0.0413V-0.0413\, V

D

0.828V-0.828\,V

Answer

0.0413V0.0413\, V

Explanation

Solution

E=E0.0591nlogQE=E^{\circ}-\frac{0.0591}{n}log\,Q E=0E^{\circ}=0 for all concentration cells =00.05911log(0.010.05)=0-\frac{0.0591}{1} log \left(\frac{0.01}{0.05}\right) =0.0413V=0.0413\,V