Question

What will be the effect on Inductive reactance ${X_L}$ and capacitive reactance ${X_C}$ , if frequency of ac source is increased?

Answer 1

In order to answer this question, first we will explain the effect on Inductive reactance when frequency of ac source is increased with their formula. And again we will explain the effect on Capacitive reactance when frequency of ac source is increased with their formula. We will also discuss both the reactants.

Complete answer: If the frequency of an ac source is increased, then the inductive reactance will be:
${X_L} = wL = 2\pi vL$ will increase.
where, $L$ is the Inductance
$v$ is the frequency.
The inductor in an AC circuit provides inductive reactance, which opposes the passage of ac current. (${X_L}$ ) is the symbol for it, and it is measured in ohms. Lower frequencies have low inductive reactance, while higher frequencies have greater inductive reactance. For continuous DC current, however, it is minimal.
Again, if the frequency of an ac source is increased, then the capacitive reactance will be:
${X_C} = \dfrac{1}{{wC}} = \dfrac{1}{{2\pi vC}}$ will decrease.
where, $C$ is the capacitance
$v$ is the frequency.
As we know, $(w = 2\pi v)$ .(it’s a constant value).
The complex impedance of a capacitor whose value fluctuates with relation to the applied frequency is known as capacitive reactance. When a DC voltage is provided to a capacitor, the capacitor draws a charging current from the supply and charges up to a value equal to the applied voltage.

Note:
With either an increase in inductance or a rise in frequency, the inductive reactance rises. As a result, the inductive reactance is proportional to the inductance and frequency. As a result, as inductance or frequency rises, the resistance to current flow rises.