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Question

Question: What will be the change in internal energy when 12 kJ of work is done on the system and 2 kJ of heat...

What will be the change in internal energy when 12 kJ of work is done on the system and 2 kJ of heat is given by the system?

A

+10 KJ

B

– 10 KJ

C
  • 5 KJ
D

– 5 KJ

Answer

+10 KJ

Explanation

Solution

: Heat evolved, = - 2 kJ

Work done on the system, = + 12 kJ

ΔU=q+W=2+12=+10kJ\Delta U = q + W = - 2 + 12 = + 10kJ