Question

What will be the bond order of the species with electronic configuration $1s^{2}2s^{2}2p^{5}$?

• A. One
• B. Two
• C. Three
• D. Zero

Answer 1

Answer: (A)

One

Answer 2

: Electronic configuration of atom : $1s^{2}2s^{2}2p^{5}$

M.O. configuration :

$(\sigma 1s^{2})(\sigma*1s^{2})(\sigma 2s^{2})(\sigma*2s^{2})(\sigma 2p_{z}^{2})$

$(\pi 2p_{x}^{2} = \pi 2p_{y}^{2})(\pi*2p_{x}^{2} = \pi*2p_{y}^{2})$

B.O. =$\frac{1}{2} \times (10 - 8) = 1$