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Question: What will be the angular momentum of a electron, if energy of this electron in H-atom is 1.5eV (in J...

What will be the angular momentum of a electron, if energy of this electron in H-atom is 1.5eV (in J-sec).

A

1.05×10−341.05 \times 10^{- 34}

B

2.1×10−342.1 \times 10^{- 34}

C

3.15×10−343.15 \times 10^{- 34}

D

−2.1×10−34- 2.1 \times 10^{- 34}

Answer

3.15×10−343.15 \times 10^{- 34}

Explanation

Solution

Energy of electron in H atom En=−13.6n2eVE_{n} = \frac{- 13.6}{n^{2}}eV

⇒−1.5=−13.6n2⇒n2=13.61.5=3\Rightarrow - 1.5 = \frac{- 13.6}{n^{2}} \Rightarrow n^{2} = \frac{13.6}{1.5} = 3

Now angular momentum

p=nh2π=3×6.6×10−342×3.14=3.15×10−34J×sec⁡p = n\frac{h}{2\pi} = \frac{3 \times 6.6 \times 10^{- 34}}{2 \times 3.14} = 3.15 \times 10^{- 34}J \times \sec