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Question: What will be the acceleration due to gravity at height h if h \>\> R. Where R is radius of earth and...

What will be the acceleration due to gravity at height h if h >> R. Where R is radius of earth and g is acceleration due to gravity on the surface of earth

A

g(1+hR)2\frac { g } { \left( 1 + \frac { h } { R } \right) ^ { 2 } }

B

g(1−2hR)g \left( 1 - \frac { 2 h } { R } \right)

C

g(1−hR)2\frac { g } { \left( 1 - \frac { h } { R } \right) ^ { 2 } }

D

g(1−hR)g \left( 1 - \frac { h } { R } \right)

Answer

g(1+hR)2\frac { g } { \left( 1 + \frac { h } { R } \right) ^ { 2 } }

Explanation

Solution

g′=g(RR+h)2=g(1+hR)2g ^ { \prime } = g \left( \frac { R } { R + h } \right) ^ { 2 } = \frac { g } { \left( 1 + \frac { h } { R } \right) ^ { 2 } }