Question
Question: What will be order of reaction and rate constant for a chemical change having t<sub>50%</sub> v/s lo...
What will be order of reaction and rate constant for a chemical change having t50% v/s log conc. (1) curve as -
A
0, 1
B
1, 1
C
2, 2
D
3, 1
Answer
0, 1
Explanation
Solution
For a reaction, t1/2 × a1–n = K(.a)1–n
log t1/2 = (1 – n) log a + log k
(y = mx + c)
1 – n = tan 45° Ž n = 0