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Question: What will be order of reaction and rate constant for a chemical change having t<sub>50%</sub> v/s lo...

What will be order of reaction and rate constant for a chemical change having t50% v/s log conc. (1) curve as -

A

0, 1

B

1, 1

C

2, 2

D

3, 1

Answer

0, 1

Explanation

Solution

For a reaction, t1/2 × a1–n = K(.a)1–n

log t1/2 = (1 – n) log a + log k

(y = mx + c)

1 – n = tan 45° Ž n = 0