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Question: What will be de-Broglie wavelength of an electron moving with a velocity of \(1.2 \times 10^{5}ms^{-...

What will be de-Broglie wavelength of an electron moving with a velocity of 1.2×105ms−11.2 \times 10^{5}ms^{- 1}

A

6.068×10−96.068 \times 10^{- 9}

B

3.133×10−373.133 \times 10^{- 37}

C

6.626×10−96.626 \times 10^{- 9}

D

6.018×10−76.018 \times 10^{- 7}

Answer

6.626×10−96.626 \times 10^{- 9}

Explanation

Solution

λ=hp\lambda = \frac{h}{p}, p=mvp = mv

λ=hmv=6.62×10−349.1×10−31×1.2×105\lambda = \frac{h}{mv} = \frac{6.62 \times 10^{- 34}}{9.1 \times 10^{- 31} \times 1.2 \times 10^{5}}

λ=6.626×10−9m\lambda = 6.626 \times 10^{- 9}m.