Question

What weight of $NaCl$ is decomposed by $4.9g$ of ${H_2}S{O_4}$if $6g$ of $NaHS{O_4}$ and $1.825g$ are produced in the same reaction?

Answer 1

In order to solve the given query we have used the concept of law of conservation of mass .The law of conservation of mass governs all chemical equations, stating that matter cannot be produced or destroyed. As a result, each element must have the same number of atoms on both sides of a chemical equation.

Complete answer:
The Sodium chloride decomposition reaction (aided by sulphuric acid) took place. $6{\text{ }}g$ of sodium hydrogen sulphate and $1.825{\text{ }}g$ of hydrogen chloride are generated in this process.
After that, the weight of sodium chloride that reacted with sulphuric acid must be determined.
That concept that will be used here to solve the problem is
Conservation of mass: The mass of the products and the mass of the reactants are the same. Every chemical reaction must produce the same amount of matter in the products as it did in the reactants. Mass is conserved in chemical reactions, according to balanced chemical equations.
Now, coming to the question;
The reaction can be given as:
$NaCl + {H_2}S{O_4} \to NaHS{O_4} + HCl$
According to conservation of mass;
${W_{\left( {NaCl} \right)}} + {W_{\left( {{H_2}S{O_4}} \right)}} = {W_{\left( {NaHS{O_4}} \right)}} + {W_{\left( {Hcl} \right)}} \\\ {W_{\left( {NaCl} \right)}} + \,\,\,\,\,\,4.9g = \,\,\,\,\,\,\,6g\,\,\,\,\,\,\, + 1.825g \\\ {W_{\left( {Nacl} \right)}} = 6 + 1.825 - 4.9 = 2.295g \\\$
Therefore, the weight of $NaCl$ decomposed is $2.295g$

Note:
However, in a nuclear fusion reaction, the energy that the sun releases in its core is due to hydrogen nuclei colliding and forming helium nuclei. Since a portion of the mass is converted into energy, the conservation of mass is violated. As a result, the law of conservation of mass is broken here.