What weight of ( HCl ) is present in ( 155, ml ) of a ( 0.54... | Chemistry | SolveeIt

Question

What weight of $HCl$ is present in $155\, ml$ of a $0.54\, M$ solution?

$3.06 \,g$

$6.12 \,g$

$1.53 \,g$

$0.30\,g$

Answer

$3.06 \,g$

Explanation

Solution

$HCl$ ; molecular weight $= 36.4\,g/mol$
$M = (g/mw)/ L$
$M \cdot L= g/m w$
$mw \times m \times L = g$
$g = (36.4 \,g/mol)(0.54 \,mol/L)$
$(155 \,mL) (1L/1000\, mL)$
$g = 3.04 g \simeq 3.06 \,g$

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