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Question: What weight of \(CaC{O_3}\) must be decomposed to produce the sufficient quantity of carbon dioxide ...

What weight of CaCO3CaC{O_3} must be decomposed to produce the sufficient quantity of carbon dioxide to convert 21.2kg21.2kg of Na2CO3N{a_2}C{O_3} completely into NaHCO3NaHC{O_3}?
[Atomic mass Na=23Na = 23 ,Ca=40Ca = 40]
CaCO3CaO+CO2CaC{O_3} \to CaO + C{O_2}
Na2CO3+CO2+H2O2NaHCO3N{a_2}C{O_3} + C{O_2} + {H_2}O \to 2NaHC{O_3}
A. 100kg100kg
B. 20kg20kg
C. 120kg120kg
D. 30kg30kg

Explanation

Solution

A chemical reaction in which one reactant breaks down into two or more products is known as a decomposition reaction.

Complete answer:
CaCO3CaO+CO2CaC{O_3} \to CaO + C{O_2}
The molecular masses of the above reactants and products is:
10056+44100 \to 56 + 44
Na2CO3+CO2+H2O2NaHCO3N{a_2}C{O_3} + C{O_2} + {H_2}O \to 2NaHC{O_3}
The molecular masses of the above reactants and products are:
106+44+18107106 + 44 + 18 \to 107
So, we have 21.2kg21.2kg of Na2CO3N{a_2}C{O_3} =21200g = 21200g of Na2CO3N{a_2}C{O_3}
The amount of CO2C{O_2} needed =21200×44106 = 21200 \times \dfrac{{44}}{{106}}
The amount of CO2C{O_2} needed=8.8kg = 8.8kg
8.8kg8.8kg of CO2C{O_2} =8800g = 8800g
As we the amount of CO2C{O_2} needed we can calculate the amount of CaCO3CaC{O_3} needed,
Amount of CaCO3CaC{O_3} needed =8800×10044 = \dfrac{{8800 \times 100}}{{44}}
Amount of CaCO3CaC{O_3} needed =20000g = 20000g
Amount of CaCO3CaC{O_3} needed =20kg = 20kg

So, the correct answer is “Option B”.

Note:
A source of energy, such as heat, light, or electricity, is required for most breakdown reactions. Even if one or more of the products are still compounds, a reaction is termed a decomposition reaction. A metal carbonate decomposes into a metal oxide and carbon dioxide gas when exposed to air.