Question
Question: What volume of water is to be added to \(100c{m^3}\) of \(0.5M\) \(NaOH\) solution to make it \(0.1M...
What volume of water is to be added to 100cm3 of 0.5M NaOH solution to make it 0.1M solution?
A. 200cm3
B. 400cm3
C. 500cm3
D. 100cm3
Solution
We have to know that dilution is the way toward diminishing the convergence of a solute in an answer, ordinarily basically by blending in with something more dissolvable like adding more water to the arrangement. To weaken an answer intends to add more dissolvable without the option of more solute. The subsequent arrangement is completely blended in order to guarantee that all pieces of the arrangement are indistinguishable.
Complete answer:
We have to know that a similar direct relationship applies to gases and fumes weakened in air for instance. Although thorough blending of gases and fumes may not be as effectively accomplished. The M1V1 rises to M2V2 condition is utilized to figure weakening. M1 is the molarity and V1 is the volume of the concentrated arrangement. M2 is the molarity and V is the volume of the weakened arrangement.
Numerically this relationship can be displayed by condition.
M1×V1=M2V2
Where, in the given details,
M1 = The initial concentration of molarity = 0.5M
M2 = The final concentration of molarity = 0.1M
V1 = The initial volume = 100cm3
V2 = The final volume
Using the above expression, calculate the final volume of the solution.
M1×V1=M2V2
Applying given values in the above equation,
0.5×100=0.1×V2
Then,
V2=500cm3
Therefore,
V=500−100=400cm3
Hence, the volume of the water is 400cm3 .
So, the correct answer is “Option B”.
Note:
We have to know that, M1×V1=M2V2 , which joins both the mole idea and the convergence of arrangements, is regularly utilized in science computations. Factors, for example, reasonable agreement and critical thinking abilities add to understudies presentation in ascertaining issues identified with the centralization of solutions rated arrangement.