Question

What volume of oxygen gas $(O_2)$ measured at $0^\circ C$ and 1 atm, is needed to bum completely 1L of propane gas $(C_3H_8)$ measured under the same conditions?

• A. 7 L
• B. 6 L
• C. 5 L
• D. 10 L

Answer 1

Answer: (C)

5 L

Answer 2

The correct answer is C:5L
$C_3H_8 + \, \, \, 50 _2 \rightarrow 3CO_2 + 4H_2O$
For the combustion of 22.4 L propane, oxygen required = $5 \times 22.4 L$
For the combustion of 1 L of propane oxygen required $\frac {5 \times 22.4}{22.4}L$
$= 5 L$