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Question: What volume of Methane at NTP is formed when 8.2 grams of \({\text{C}}{{\text{H}}_3}{\text{COONa}}\)...

What volume of Methane at NTP is formed when 8.2 grams of CH3COONa{\text{C}}{{\text{H}}_3}{\text{COONa}} is it treated with soda lime?
A.4.4 ml
B.3.7 ml
C.2.2 ml
D.5.6 ml

Explanation

Solution

NTP stands for natural temperature and pressure, while STP stands for regular temperature and pressure. The STP values for temperature and pressure for gas, according to IUPAC, are 273.15 K and 0.987 atm, respectively. The NTP temperature and pressure values are 293.15 K and 1atm, respectively.
Formula used
No. of moles = Given Molecular MassMolecular Mass{\text{No}}{\text{. of moles = }}\dfrac{{{\text{Given Molecular Mass}}}}{{{\text{Molecular Mass}}}}

Complete answer:
The net reaction for the question can be given as
CH3COONa+NaOHCH4+Na2CO3{\text{C}}{{\text{H}}_3}{\text{COONa}} + {\text{NaOH}} \to {\text{C}}{{\text{H}}_4} + {\text{N}}{{\text{a}}_2}{\text{C}}{{\text{O}}_3}
From the above reaction, it is evident that 1 mole of CH3COONa{\text{C}}{{\text{H}}_3}{\text{COONa}}will produce 1 mole of CH4{\text{C}}{{\text{H}}_4}
The molecular weight of CH3COONa{\text{C}}{{\text{H}}_3}{\text{COONa}} can be calculated as
m(CH3COONa)=82  gm(\left. {{\text{C}}{{\text{H}}_3}{\text{COONa}}} \right) = 82\;{\text{g}}
To find the number of moles we calculate as follows
 No. of moles in 8.2  g of CH3COONa=8.282=0.1  mole{\text{ No}}{\text{. of moles in }}8.2\;{\text{g of C}}{{\text{H}}_3}{\text{COONa}} = \dfrac{{8.2}}{{82}} = 0.1\;{\text{mole}}
Hence it is evident that 0.1 mole of CH3COONa{\text{C}}{{\text{H}}_3}{\text{COONa}} will produce 0.1 mole of CH4C{H_4}
The molecular weight of CH4C{H_4} can be calculated as
m(CH4)=16  gm(\left. {C{H_4}} \right) = 16\;{\text{g}}
mole of methane contains 16 x 0.1=1.6 g of methane
The term "density" refers to the amount of mass per unit of volume. An object's average density is proportional to its total mass divided by its total volume. An object composed of a more dense material (such as iron) would have less volume than one made of a less dense substance of comparable mass (such as water).
Density of methane =0.4256 g/ml
Volume = MassDensity{\text{Volume = }}\dfrac{{Mass}}{{Density}}
V=1.60.4256=3.75mlV = \dfrac{{1.6}}{{0.4256}} = 3.75{\text{ml}}
Therefore the volume of methane generated will be 3.75 ml

Note:
Methane is a chemical present in trace amounts in the Earth's atmosphere. The simplest hydrocarbon is methane, which is made up of one carbon atom and four hydrogen atoms. Methane is an extremely potent greenhouse gas. Methane is a flammable gas that is used as a fuel all over the world. Carbon gas has a significant amount of it.