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Question: What volume of dihydrogen at \({{20}^{\circ }}C\) and one bar will be released when 0.15 g of alumin...

What volume of dihydrogen at 20C{{20}^{\circ }}C and one bar will be released when 0.15 g of aluminium reacts with the caustic soda to produce hydrogen?

Explanation

Solution

As we know that sodium hydroxide is also called caustic soda. Here we can see that hydrogen is basically referred to as the hydrogen molecule that contains two hydrogen atoms in it. Here, di-means two.

Complete step-by-step answer: - We can write the reaction when Drainex contains small bits of aluminium which react with the caustic soda to produce dihydrogen as:
2Al(s)+2NaOH(aq)+2H2O(l)2NaAlO2(aq)+3H2(g)2Al(s)+2NaOH(aq)+2{{H}_{2}}O(l)\to 2NaAl{{O}_{2}}(aq)+3{{H}_{2}}(g)
- From the above reaction we can find that the two moles of aluminium release the three moles of hydrogen gas.
- Now, we will calculate the moles of aluminium produced as:
=0.15g27=5.56×103moles=\dfrac{0.15g}{27}=5.56\times {{10}^{-3}}moles
- Hence, we can write the moles of hydrogen produced as:
=32×5.56×103moles =8.33×103moles \begin{aligned} & =\dfrac{3}{2}\times 5.56\times {{10}^{-3}}moles \\\ & =8.33\times {{10}^{-3}}moles \\\ \end{aligned}
- Hence, we can calculate the volume of hydrogen as:

& {{H}_{2}}=\dfrac{nRT}{P} \\\ & =\dfrac{8.33\times {{10}^{-3}}\times 0.0831\times 293}{1} \\\ & =0.203litres \\\ \end{aligned}$$ \- Hence, we get the value of the volume of dihydrogen released by the reaction as 0.203 litres. \- Hence, we can conclude that the correct answer is 0.203 volume of dihydrogen at ${{20}^{\circ }}C$ and one bar will be released. **Note:** \- As we know that ideal gas equation has many applications like from solving various problems as shown above to some of the difficult equations. \- There are some properties of drain cleaner like a dream cleaner is basically a chemical compound that unlocks the blocked wastewater drains and also unlocks sewer pipes.