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Question

Question: What percentage of original radioactive atoms is left after five half lives....

What percentage of original radioactive atoms is left after five half lives.

A

0.3%

B

1%

C

31%

D

3.125%

Answer

3.125%

Explanation

Solution

Fraction of atoms remains after five half lives

NN0=(12)t/T=(12)5T/T=132\frac{N}{N_{0}} = \left( \frac{1}{2} \right)^{t/T} = \left( \frac{1}{2} \right)^{5T/T} = \frac{1}{32}.

⇒ Percentage atom remains

=132×100=3.125%= \frac{1}{32} \times 100 = 3.125\%