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Question

Question: What percent of \(12kg\) is \(725gm\) ?...

What percent of 12kg12kg is 725gm725gm ?

Explanation

Solution

In the given question, we are required to calculate the percentage that corresponds to 725gm725gm of the whole quantity 12kg12kg. So, we can find the percentage for 725gm725gm of 12kg12kg by using the formula of percentage as Percentage=ab×100%Percentage = \dfrac{a}{b} \times 100\% where a is the number whose percentage is to be calculated and b is the number that corresponds to whole.

Complete step by step answer:
In this specific question, we have to find the percentage that corresponds to 725gm725gm out of 12kg12kg.
So, we have to find what percent corresponds to 725gm725gm when the whole 100100 percent corresponds to 12kg12kg. So, we can calculate the percent of 725gm725gm of 12kg12kg using the formula Percentage=ab×100%Percentage = \dfrac{a}{b} \times 100\% .
In this formula, a is the number whose percentage is to be found and b is the number that constitutes the entire 100100 percent.
Here, a=725a = 725 grams and b=12b = 12 kilograms.
Now, we would have to convert the numbers into the same units so as to find the percentage.
We know that one kilogram is equal to a thousand gram. So, we have, 1kg=1000gm1kg = 1000gm.
Hence, we get, 12kg=12000g12kg = 12000g.
Now, substituting the values of a and b in to the formula, we get,
Percentage=72512000×100%Percentage = \dfrac{{725}}{{12000}} \times 100\%
Cancelling out the common factors in numerator and denominator, we get,
Percentage=14524%\Rightarrow Percentage = \dfrac{{145}}{{24}}\%
Doing the calculations, we get,
Percentage=6.04%\Rightarrow Percentage = 6.04\%
Therefore, 6.04%6.04\% of 1212 kilograms is 725725 grams.
This is our required final answer for the given problem.

Note:
There are various methods to find an answer to the given question, but the method described above is the simplest one. We can also consider solving the problem using the unitary method by taking the original number as 100%100\% of itself and then computing the change percent in comparison to the original number. Work as many problems as possible to crack these types of problems in a limited time period.