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Question

Question: What must be the relation between length 'L' and radius 'R' of the cylinder if its moment of inertia...

What must be the relation between length 'L' and radius 'R' of the cylinder if its moment of inertia about its axis is equal to that about the equatorial axis ?

A

L = R

B

L = 2R

C

L = 3R

D

L = 3\sqrt{3}R

Answer

L = 3\sqrt{3}R

Explanation

Solution

mR22\frac{mR^{2}}{2} = M (L212+R24)\left( \frac{L^{2}}{12} + \frac{R^{2}}{4} \right)

or R22\frac{R^{2}}{2}= L212\frac{L^{2}}{12}+ R24\frac{R^{2}}{4}

or L = 3\sqrt{3}R