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Question: What may be the correct orbital notation if the wave function is – ψ = \(\frac{1}{81\sqrt{6\pi}}\lef...

What may be the correct orbital notation if the wave function is – ψ = 1816π(1a0)3/2\frac{1}{81\sqrt{6\pi}}\left( \frac{1}{a_{0}} \right)^{3/2}σ2 e–σ/3 (3 cos2q –1);

Here σ = r/a0 and a0 = h20πme2\frac{h^{2} \in_{0}}{\pi me^{2}}

A

4s

B

2px

C

3py

D

3dz23d_{z}^{2}

Answer

3dz23d_{z}^{2}

Explanation

Solution

y = 0 if cos2 q = 1/3

Ž cosq = ± 13\frac{1}{\sqrt{3}}

So there are two angular nodes for this orbital hence

l = 2 i.e. orbital should be 3dz23d_{z}^{2}