Question

What mass of N₂H₄ can be oxidised to N₂­ by 24 gm of K₂CrO₄ which is reduced to Cr(OH)₄^– ?

• A. 2.969 gm
• B. 5.25 gm
• C. 9.08 gm
• D. 29.69 gm

Answer 1

Answer: (A)

2.969 gm

Answer 2

Moles of K₂CrO₄ reacted = $\frac{24}{194}$ moles.

4 moles of K₂CrO₄ reacts with 3 mole of N₂H₄

\ $\frac{24}{194}$ moles of K₂CrO₄ reacts with

$\frac{3}{4}$× $\frac{24}{194}$ moles of N₂H₄

\ amount of N₂H₄ reacted = $\frac{3}{4}$× $\frac{24}{194}$ moles

= $\frac{3}{4}$× $\frac{24}{194}$× 32 gm = 2.969 gm