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Chemistry Question on Stoichiometry and Stoichiometric Calculations

What mass of 95% pure CaCO3CaCO_3 will be required to neutralise 50 mL of 0.5 M HClHCl solution according to the following reaction?
CaCO3(s)+2HCl(aq)→CaCl2(aq)+CO2(g)+2H2O(l)CaCO_3(s) + 2HCl(aq) → CaCl_2(aq) + CO_2(g) + 2H_2O(l)
[Calculate upto second place of decimal point]

A

1.25 g

B

1.32 g

C

3.65 g

D

9.50 g

Answer

1.32 g

Explanation

Solution

The correct option is (B): 1.32 g