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Question

Chemistry Question on Electrolysis

What is X in the following reaction? KHSO4+F2HF+XKHS{{O}_{4}}+{{F}_{2}}\xrightarrow{{}}HF+X

A

K2SO4{{K}_{2}}S{{O}_{4}}

B

K2S2O4{{K}_{2}}{{S}_{2}}{{O}_{4}}

C

K2S2O2{{K}_{2}}{{S}_{2}}{{O}_{2}}

D

K2S2O8{{K}_{2}}{{S}_{2}}{{O}_{8}}

Answer

K2S2O8{{K}_{2}}{{S}_{2}}{{O}_{8}}

Explanation

Solution

The balanced equation is 2KHS{{O}_{4}}+{{F}_{2}}\xrightarrow{{}}2HF+\underset{(X)}{\mathop{{{K}_{2}}{{S}_{2}}O{{ & }_{8}}}}\, Therefore, X is K2S2O8.{{\text{K}}_{\text{2}}}{{\text{S}}_{\text{2}}}{{\text{O}}_{\text{8}}}\text{.}