Question

What is the work done when 1 mole of a gas expands isothermally from 25 L to 250 L at a constant pressure of 1 atm and a temperature of 300 K?

• A. – 3542J
• B. – 5744 J
• C. – 2657 J
• D. – 4890 J

Answer 1

Answer: (B)

– 5744 J

Answer 2

: Work done in reversible isothermal expansion,

$W = - 2.303nRT\log\frac{V_{f}}{V_{i}}$

$= - 2.303 \times 1 \times 8.314 \times 300 \times \log\frac{250}{25} = - 5744.14J$