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Question

Question: What is the weight per volume method to calculate concentration?...

What is the weight per volume method to calculate concentration?

Explanation

Solution

Hint : WeightVolume\dfrac{{Weight}}{{Volume}} percentage concentration is a measurement of the concentration of a solution. WeightVolume\dfrac{{Weight}}{{Volume}} percentage concentration is usually called aswv(%)\dfrac{w}{v}\left( \% \right). Common units forwv(%)\dfrac{w}{v}\left( \% \right) concentration areg100ml(%)\dfrac{g}{{100ml}}\left( \% \right). The state of being soluble in a given amount of substance is known as solubility which is expressed in terms of concentration also.

Complete Step By Step Answer:
WeightVolume\dfrac{{Weight}}{{Volume}} is the same as massvolume\dfrac{{mass}}{{volume}}. It is the weight of solute divided by the volume of solution multiplied by 100100: %wv=weight of solutevolume of solution×100\% \dfrac{w}{v} = \dfrac{{{\text{weight of solute}}}}{{{\text{volume of solution}}}} \times 100
For example: What is the weightvolume\dfrac{{weight}}{{volume}} percentage concentration of 500ml500mlaqueous acetic acid(CH3COOH)\left( {C{H_3}COOH} \right) solution containing10g CH3COOH10g{\text{ C}}{{\text{H}}_3}COOH?
Firstly we write the equation used to calculate theweightvolume(%)\dfrac{{weight}}{{volume}}\left( \% \right):
=wv%=mass of solutevolume of solution×100= \dfrac{w}{v}\% = \dfrac{{{\text{mass of solute}}}}{{{\text{volume of solution}}}} \times 100
Now, find the solute: solute==acetic acid(CH3COOH)\left( {C{H_3}COOH} \right)
After that, read out the data from the question: mass of soluteCH3COOH=10gC{H_3}COOH = 10g
Volume of solution=500ml = 500ml
Put all the values in the formula and solve it:
wv%=10500×100\dfrac{w}{v}\% = \dfrac{{10}}{{500}} \times 100
=2%= 2\%

Note :
WeightVolume\dfrac{{Weight}}{{Volume}} percent concentrations are characteristic when solids are dissolved in liquids and are mainly used because of the reason that volume is easier to calculate and measure than weight. One more important reason for using this percent concentration is the fact that dilute solutions have a density that’s generally close to1 gml11{\text{ gm}}{{\text{l}}^{ - 1}}, which makes the volume of the solution expressed in ml numerically equal to the mass of the solution expressed in grams. As a conclusion, in order to calculate a wv\dfrac{w}{v} percent concentration, we must determine how much quantity of solute is present, it’s mass in grams and how much volume of solution is present in ml. It is mainly used when a dry solute is weighed out and added to a liquid solvent commonly water(H2O)\left( {{H_2}O} \right).