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Question

Chemistry Question on Organic Chemistry- Some Basic Principles and Techniques

What is the weight of oxygen required for the complete combustion of 2.8 kg of ethylene?

A

2.8 kg

B

6.4 kg

C

9.6 kg

D

96 kg

Answer

9.6 kg

Explanation

Solution

(C) \begin {array} \ C_2 H_4 \\\ {12\times 2 + 4 \times 1} \\\ =28g \end{array} + \begin {array} \ \ \ 3O_2 \\\ {16\times 6} \\\ =96g \end{array} \rightarrow 2CO_2 + 2H_2O ∴\therefore For the combustion of 28×10−328 \times 10^{-3} kg of ethylene oxygen required =96×10−3 kg= 96 \times 10^{-3} \ kg ∴\therefore For the combustion of 2.8 kg of ethylene oxygen required 96×10−3×2.828×10−3=9.6kg \frac {96 \times 10^{-3} \times 2.8}{28 \times 10^{-3}} = 9.6 kg