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Question: What is the weight of 0.1 moles of \(N{{a}_{2}}C{{O}_ {3}} \) (A) 10g (B) 5g (C) 10.6g (D) ...

What is the weight of 0.1 moles of Na2CO3N{{a}_{2}}C{{O}_ {3}}
(A) 10g
(B) 5g
(C) 10.6g
(D) 12.6g

Explanation

Solution

To find the atomic weight of the given compound we will be using the formula: number of moles = weight ÷\div molar mass as we have been given the number of moles of Na2CO3N{{a}_{2}}C{{O}_ {3}} .

Complete answer:
We have been provided that the number of moles of Na2CO3N{{a}_{2}}C{{O}_ {3}} are 0.1 moles,
We need to find the atomic weight,
So, for that:
We will be using the formula: number of moles = weight ÷\div molar mass,
And we have been provided that number of moles of Na2CO3N{{a}_{2}}C{{O}_ {3}} is 0.1 moles,
And we can find the molar mass of Na2CO3N{{a}_{2}}C{{O}_ {3}} ,
Molar mass of any compound can be easily be calculated by simply adding the standard atomic masses of the constituent elements,
So, we will find the molar mass of Na2CO3N{{a}_{2}}C{{O}_ {3}} , by the adding the atomic weights of Na, C and O:
Which would be come out to be: (23×2)+12+(3×16)=46+12+48(23\times 2) +12+(3\times 16) =46+12+48,
So, the molar mass of Na2CO3N{{a}_{2}}C{{O}_ {3}} comes out to be: 106,
Now keeping these values in the formula: number of moles = weight ÷\div molar mass,
So, the equation would be: 0.1=weight1060.1=\dfrac{weight}{106} ,
So, the weight comes out to be: 0.1×106=10.6g0.1\times 106=10.6g,
So, the weight of Na2CO3N{{a}_{2}}C{{O}_ {3}} comes out to be 10.6g.

So, we can conclude that the correct option is (C).

Note:
Na2CO3N{{a}_{2}}C{{O}_ {3}} is also known as washing soda and it has a lot of application, as it is used as a cleansing agent for household purposes, even for removing the hardness of water, to manufacture glass, soap and paper.