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Question: What is the wavelength of the radiation with photon energy which is the mean value of photon energie...

What is the wavelength of the radiation with photon energy which is the mean value of photon energies of radiations with wavelengths l1 = 4000 Å and l2 = 6000 Å ?

A

5000 Å

B

5200 Å

C

5600 Å

D

4800 Å

Answer

4800 Å

Explanation

Solution

hcλ3\frac{hc}{\lambda_{3}} = hcλ1+hcλ22\frac{\frac{hc}{\lambda_{1}} + \frac{hc}{\lambda_{2}}}{2}

̃ 1λ3\frac{1}{\lambda_{3}}= 12\frac{1}{2} (1λ1+1λ2)\left( \frac{1}{\lambda_{1}} + \frac{1}{\lambda_{2}} \right)

= 12\frac{1}{2} (14000+16000)\left( \frac{1}{4000} + \frac{1}{6000} \right)

̃ l3 = 4800 Å