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Question

Chemistry Question on Structure of atom

What is the wavelength (in mm ) of a particle of mass 6.62×10−29g6.62 \times 10^{-29} g moving with a velocity of 103ms−1?10^{3} ms ^{-1} ?

A

6.62×10−4 6.62\times 10^{-4}

B

6.62×10−3 6.62\times 10^{-3}

C

10−510^{-5}

D

10510^{5}

Answer

10−510^{-5}

Explanation

Solution

According to de-Broglie equation
λ=hmv\lambda =\frac{h}{m v}
=6.62×10−346.62×10−29×10−3×103=\frac{6.62 \times 10^{-34}}{6.62 \times 10^{-29} \times 10^{-3} \times 10^{3}}
=10−5m=10^{-5} m