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Question

Chemistry Question on Quantum Mechanical Model of Atom

What is the wavelength (in mm ) of a particle of mass 6.62×10−29g6.62\times {{10}^{-29}}g moving with a velocity of 103  ms−1{{10}^{3}}\,\,m{{s}^{-1}} ?

A

6.62×10−46.62\times {{10}^{-4}}

B

6.62×10−36.62\times {{10}^{-3}}

C

10−5{{10}^{-5}}

D

105{{10}^{5}}

Answer

10−5{{10}^{-5}}

Explanation

Solution

According to de-Broglie equation λ=hmv\lambda =\frac{h}{mv} =6.62×10−346.62×10−29×10−3×103=\frac{6.62\times {{10}^{-34}}}{6.62\times {{10}^{-29}}\times {{10}^{-3}}\times {{10}^{3}}} =10−5m={{10}^{-5}}m