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Question: What is the volume of oxygen required for complete combustion of 0.25 mole of methane at stp...

What is the volume of oxygen required for complete combustion of 0.25 mole of methane at stp

Answer

11.2 L

Explanation

Solution

  1. Write the balanced equation for methane combustion:

    CH4+2O2→CO2+2H2O\text{CH}_4 + 2\text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O}

  2. From the equation, 1 mole of CH₄ requires 2 moles of O₂.
    So, 0.25 moles of CH₄ require:

    0.25×2=0.5 moles O20.25 \times 2 = 0.5 \text{ moles O}_2

  3. At STP, 1 mole of any ideal gas occupies 22.4 L.
    Thus, the volume of 0.5 moles of O₂ is:

    0.5×22.4 L=11.2 L0.5 \times 22.4~\text{L} = 11.2~\text{L}