Question

What is the volume of $6.00g$ of helium gas at STP?

Answer 1

For any given ideal gas, one mole of ideal gas occupies $22.4litres$ of volume at STP. STP is the standard reference point of temperature $(273.15k{\text{ or }}{{\text{0}}^ \circ }C)$ and pressure $(1atm{\text{ or 1}}{{\text{0}}^5}pascals)$ used when measuring gases.
Formula used : $mole = \dfrac{{{\text{given mass}}}}{{{\text{atomic mass}}}}$
$mole = \dfrac{{volume}}{{22.4L}}$

Complete answer:
The atomic weight of helium is $4gmo{l^{ - 1}}$. When we are given mass , we can convert it into a number of moles present. This helps us to calculate volume.
To find one mole, the formula is $mole = \dfrac{{{\text{given mass}}}}{{{\text{atomic mass}}}}$
The given mass is $6.00g$ of helium.
So the number of moles of helium will be: = \dfrac{{6g}}{{4gmo{l^{ - 1}}}}$$$$ = 1.5mole
Now we know that one mole of helium gas occupies $22.4L$ of volume.
$mole = \dfrac{{volume}}{{22.4L}}$
So, volume occupied by $1.5mole$ is $= 1.5mole$ $\times 22.4L = 33.6Lmole$

Additional Information: Helium is a chemical element with the symbol $'He'$ and atomic number is $2$. It is colourless, odourless, tasteless, inert, non-toxic, monoatomic gas. Its boiling point is lower than all other elements. Helium is second lightest and second most abundant .Its abundance is similar to this in both the sun and Jupiter. This is due to very high nuclear binding energy per nucleon of helium$- 4$, with respect to the other three elements after helium. Helium is used to inflate balloons in parties. It is also used as an inert shield for arc welding, for pressurizing liquid-fuelled rocket fuel tanks.

Note:
The answer will always be in the SI unit or in the form the question is asking for. So it is important to convert the units properly according to the question. Focus on whether a question asks for STP or something else. Sometimes the answer is wrong due to incorrect methods applied.