Question

What is the velocity of electron present in first Bohr orbit of hydrogen atom?

• A. $2.18 \times 10^{5}$ m/s
• B. $2.18 \times 10^{6}$m/s
• C. $2.18 \times 10^{- 18}$m/s
• D. $2.18 \times 10^{- 9}$m/s

Answer 1

Answer: (B)

$2.18 \times 10^{6}$m/s

Answer 2

: From Bohr’s theory,

$v = 2.18 \times 10^{6} \times \frac{Z}{n}m/s$

$= 2.18 \times 10^{6} \times \frac{1}{1} = 2.18 \times 10^{6}$ m/s