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Question: What is the value of \(\tan \left( {{{180}^ \circ } - \theta } \right)\) ?...

What is the value of tan(180θ)\tan \left( {{{180}^ \circ } - \theta } \right) ?

Explanation

Solution

The given question deals with basic simplification of trigonometric function by using some of the simple trigonometric formulae. We must know the compound angle formula for tangent trigonometric function tan(AB)=tanAtanB1+tanAtanB\tan \left( {A - B} \right) = \dfrac{{\tan A - \tan B}}{{1 + \tan A\tan B}}. Basic algebraic rules and trigonometric identities are to be kept in mind while doing simplification in the given problem.

Complete step by step answer:
In the given problem, we have to simplify the expression tan(180θ)\tan \left( {{{180}^ \circ } - \theta } \right) and find its value.
So, we use the compound angle formula of tangent tan(AB)=tanAtanB1+tanAtanB\tan \left( {A - B} \right) = \dfrac{{\tan A - \tan B}}{{1 + \tan A\tan B}} in order to simplify the value of the expression given to us.
So, we have, tan(180θ)\tan \left( {{{180}^ \circ } - \theta } \right)
Here, A=180A = {180^ \circ } and B=θB = \theta .
tan(180θ)=tan180tanθ1+tan180tanθ\Rightarrow \tan \left( {{{180}^ \circ } - \theta } \right) = \dfrac{{\tan {{180}^ \circ } - \tan \theta }}{{1 + \tan {{180}^ \circ }\tan \theta }}
Now, we know that the value of tan180\tan {180^ \circ } is equal to zero. Hence, we get,
tan(180θ)=0tanθ1+(0)tanθ\Rightarrow \tan \left( {{{180}^ \circ } - \theta } \right) = \dfrac{{0 - \tan \theta }}{{1 + \left( 0 \right)\tan \theta }}
Now, simplifying the expression, we get,
tan(180θ)=tanθ\therefore \tan \left( {{{180}^ \circ } - \theta } \right) = - \tan \theta

So, the value of tan(180θ)\tan \left( {{{180}^ \circ } - \theta } \right) is equal to tanθ- \tan \theta.

Additional information:
Trigonometric functions are also called Circular functions. Trigonometric functions are the functions that relate an angle of a right angled triangle to the ratio of two side lengths. There are 66trigonometric functions, namely: sin(x)\sin (x), cos(x)\cos (x), tan(x)\tan (x),cosec(x)\cos ec(x), sec(x)\sec (x) and cot(x)\cot \left( x \right) . Also, cosec(x)\cos ec(x) ,sec(x)\sec (x) and cot(x)\cot \left( x \right)are the reciprocals of sin(x)\sin (x), cos(x)\cos (x) and tan(x)\tan (x) respectively.

Note: Given problem deals with Trigonometric functions. For solving such problems, trigonometric formulae should be remembered by heart such as: tan(AB)=tanAtanB1+tanAtanB\tan \left( {A - B} \right) = \dfrac{{\tan A - \tan B}}{{1 + \tan A\tan B}} and tan(A+B)=tanA+tanB1tanAtanB\tan \left( {A + B} \right) = \dfrac{{\tan A + \tan B}}{{1 - \tan A\tan B}} . Besides these simple trigonometric formulae, trigonometric identities are also of significant use in such type of questions where we have to simplify trigonometric expressions with help of basic knowledge of algebraic rules and operations.However, questions involving this type of simplification of trigonometric ratios may also have multiple interconvertible answers.