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Question

Physics Question on LCR Circuit

What is the value of inductance LL for which the current is maximum in a series LCRLCR circuit with C=10μFC=10 \, \mu F and ω=1000S1 \omega=1000 \, S^{-1} ?

A

1 mH

B

cannot be calculated unless R is known

C

10 mH

D

100 mH.

Answer

100 mH.

Explanation

Solution

Current is maximum at resonance
ω2=1LC\Rightarrow \omega^{2}=\frac{1}{L C}
L=1ω2C\Rightarrow L=\frac{1}{\omega^{2} C}
=1(1000)2(10×106)=0.1H=\frac{1}{(1000)^{2}\left(10 \times 10^{-6}\right)}=0.1 \,H
=100mH=100\, mH