Question

What is the value of $h\left( -3 \right)$ if $h\left( x \right)={{x}^{2}}-x$?

Answer 1

In this problem, we have to find the value of $h\left( -3 \right)$ if $h\left( x \right)={{x}^{2}}-x$. We can see that, we are given the value of x, here we have to, just substitute the given -3 in $h\left( -3 \right)$, in the given equation $h\left( x \right)={{x}^{2}}-x$ to get the required value. We can then square the first term and add it with the next term to get the final answer.

Complete step-by-step solution:
Here we have to find $h\left( -3 \right)$.
We know that the given equation is,
$\Rightarrow h\left( x \right)={{x}^{2}}-x$
We can see that from the above given data, we have to find the value of $h\left( -3 \right)$, so we can substitute the number -3 in the place of x, we get
$\Rightarrow h\left( -3 \right)={{\left( -3 \right)}^{2}}-\left( -3 \right)$
We can now simplify the above step, as we can see that we have square of negative term, which becomes positive and the square of number 3 is 9 and we can multiply the both negative sign and assign it as positive, we get
$\Rightarrow h\left( -3 \right)=9+3$
We can now simplify the above step by adding the terms in the right-hand side, we get
$\Rightarrow h\left( -3 \right)=12$
Therefore, the value of $h\left( -3 \right)=12$.

Note: Students make mistakes where we have to multiply the negative signs to assign it as positive. We should also remember some of the square terms to be written when needed as we know square of 3 is 9. We should also remember that the square of a negative term is always positive.