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Question: What is the value of \(\Delta {H_{AB}}\) \(\left( {in\;kJ} \right)\) for a fluid in the given proces...

What is the value of ΔHAB\Delta {H_{AB}} (in  kJ)\left( {in\;kJ} \right) for a fluid in the given process represented in the figure? Heat supplied during the process =  2740  kJ = \,\;2740\;kJ.

A.40  kJ40\;kJ
B.400  kJ400\;kJ
C.1640  kJ1640\;kJ
D.None of these

Explanation

Solution

When a process takes place under constant pressure, the change in Enthalpy is equivalent to the heat absorbed or released. Enthalpy is also termed as “heat content”. The word enthalpy is a Greek word meaning ‘warming”.

Complete answer:
Enthalpy is summation of internal energy(U)\left( U \right) and the product of pressure(P)\left( P \right) and volume(V)\left( V \right). The formula of enthalpy is:
H=U+pVH = U + pV
Where, H=  Enthalpy  ofthesystemH = \;Enthalpy\;of\,the\,system
U=Internal  energy  ofthesystemU = Internal\;energy\;of\,the\,system
p=Pressure of the system  p = Pressure{\text{ }}of{\text{ }}the{\text{ }}system\;
V = Volume of the systemV{\text{ }} = {\text{ }}Volume{\text{ }}of{\text{ }}the{\text{ }}system
We cannot measure enthalpy directly but the change in enthalpy (ΔH)\left( {\Delta H} \right)can be measured which is the loss or addition of heat in the system. It always depends upon TT, pp and UU.
The formula of change in enthalpy is:
ΔH=ΔU+ΔPV\Delta H = \Delta U + \Delta PV
Entropy and enthalpy are different. They can be used interchangeably. But there is a great difference in both of them.

S.No.EntropyEnthalpy
1Entropy is the property which helps in the measurement of the movement of molecules.Enthalpy is the energy which is composed of both internal energy and energy flow.
2It is regarded only under limitations or controlled conditions.It is measured or applicable under normal or regular conditions.
3Joule per Kelvin is the unit of measurement.Joule per mole is the unit of measurement.
4The maximum amount of Entropy is favoured by the thermodynamic system.The minimum amount of Enthalpy is favoured by the thermodynamic system.

Here,
PΔV=  1  bar×  2  m3P\Delta V = \;1\;bar \times \;2\;{m^3}
PΔV=  2  bar  m3P\Delta V = \;2\;bar\;{m^3}
PΔV=  200000  JP\Delta V = \;200000\;J
=  200  kJ= \;200\;kJ
ΔH=2740  kJ+200  kJ\Delta H = - 2740\;kJ + 200\;kJ
ΔH=2540  kJ\Delta H = - 2540\;kJ
Thus, the right answer is the (d)\left( d \right) option, none of these.

Note:
If the heat given out by the system into the surrounding, it is called an exothermic reaction and the heat given to the system from the surrounding is known as endothermic reaction. Exothermic reactions don’t contain much energy within them.