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Question: What is the value of \[1 - 2 + 3 - 4 + 5 - ... + 101\]? A) 51 B) 55 C) 110 D) 111...

What is the value of 12+34+5...+1011 - 2 + 3 - 4 + 5 - ... + 101?
A) 51
B) 55
C) 110
D) 111

Explanation

Solution

Here, we will first separate the terms with negative signs and positive signs. Then we use the formula of first nn odd numbers, n2{n^2} in the first part of the obtained expression and the formula of nn natural numbers, in the second part of the obtained expression. Then we will simplify it to find the required value.

Complete step by step solution: We are given that 12+34+5...+1011 - 2 + 3 - 4 + 5 - ... + 101.

First, we will write the terms with negative signs and positive signs separately in the above expression.

(1+3+5+...+101)(2+4+6+...+100) \Rightarrow \left( {1 + 3 + 5 + ... + 101} \right) - \left( {2 + 4 + 6 + ... + 100} \right)

On taking 2 common from the second part of the above expression, we get

(1+3+5+...+101)2(1+2+3+...+50) ......eq.(1) \Rightarrow \left( {1 + 3 + 5 + ... + 101} \right) - 2\left( {1 + 2 + 3 + ... + 50} \right){\text{ ......eq.(1)}}

We have seen that the first part of the above equation is a sum of first nn odd numbers and the second part is a sum of first nn natural numbers.

Since there are 51 terms in the first sum of the above expression, then the value of nn is 51.

We will now use the formula to the sum of odd numbers is n2{n^2} in the first part of the above equation by replacing 51 for nn, we get

512 51×51 2601  \Rightarrow {51^2} \\\ \Rightarrow 51 \times 51 \\\ \Rightarrow 2601 \\\

Substituting the above value in the equation (1) to simplify it, we get

26012(1+2+3+...+50) \Rightarrow 2601 - 2\left( {1 + 2 + 3 + ... + 50} \right)
Using the formula of sum of nn natural numbers, 1+2+3+...+n=n(n+1)21 + 2 + 3 + ... + n = \dfrac{{n\left( {n + 1} \right)}}{2} in second part of the above expression where n=50n = 50, we get

2601250(50+1)2 260150(50+1) 260150(51) 26012550 51  \Rightarrow 2601 - 2\dfrac{{50\left( {50 + 1} \right)}}{2} \\\ \Rightarrow 2601 - 50\left( {50 + 1} \right) \\\ \Rightarrow 2601 - 50\left( {51} \right) \\\ \Rightarrow 2601 - 2550 \\\ \Rightarrow 51 \\\

Thus, the value of 12+34+5...+1011 - 2 + 3 - 4 + 5 - ... + 101 is 51.

Hence, option A is correct.

Note: While solving these types of problems, students should use the first, second and third term to find the general format of this series. The key concept of this question is to find the formulas of finite series. The numbers in the sum 1+3+5+...+1011 + 3 + 5 + ... + 101 is 50 instead of 51 can be confusing sometimes.