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Question

Question: What is the value of \(0^\circ \,\,F\) in Celsius scale?...

What is the value of 0F0^\circ \,\,F in Celsius scale?

Explanation

Solution

First learn the relation between Fahrenheit and Celsius scale. By applying their relationship formula we can solve the above given problem with the help of the data given in this question.

Formula Used:
F329=C5\boxed{\dfrac{{F - 32}}{9} = \dfrac{C}{5}}
Where, FF= Fahrenheit and CC= Celsius.

Complete step by step answer:
Both Fahrenheit and Celsius scale are temperature scales with the help of which we can measure the temperature and these two scales are their two different units. Celsius scale, also known as centigrade scale, is a temperature scale that is based on the freezing point of water at 0C0^\circ \,\,C and the boiling point of Water at 100C100^\circ \,\,C. Fahrenheit scale is a temperature scale that is based on the freezing point of water at 32F32^\circ \,\,F and the boiling point of water at 212F212^\circ \,\,F.We know that,
F329=C5\dfrac{{F - 32}}{9} = \dfrac{C}{5}

As given in the problem, we need to convert the given Fahrenheit value to its respective Celsius scale.
Given= 0F0^\circ \,\,F
To Find: C=??C = ??
By applying formula we get,
F329=C5\dfrac{{F - 32}}{9} = \dfrac{C}{5}
Putting the given values we get,
0329=C5\Rightarrow \dfrac{{0 - 32}}{9} = \dfrac{C}{5}
329=C5\Rightarrow \dfrac{{ - 32}}{9} = \dfrac{C}{5}
By rearranging the above equation we get,
32×59=C\dfrac{{ - 32 \times 5}}{9} = C
C=(160)9\Rightarrow C = \dfrac{{\left( { - 160} \right)}}{9}
C=(17.78)\therefore C = \left( { - 17.78} \right)

Therefore 17.78 - 17.78 is the value of 0F0^\circ \,\,F in Celsius scale.

Note: This is a simple problem while solving, always use the accurate formula. Sometime many get confused while writing the formula in place of FF some write CC which makes the whole answer incorrect and always remember CC value should be less than FF value if this will not occur then you must have made some mistake, recheck your answer.