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Question: What is the total number of electrons in a \( M{g^{2 + }} \) ion?...

What is the total number of electrons in a Mg2+M{g^{2 + }} ion?

Explanation

Solution

Hint : An atom comprises a nucleus having neutrons and protons which are surrounded by electrons in orbits. Number of protons (atomic number i.e. ‘ ZZ ’) can be considered to be equal to the total number of electrons in a neutral atom. The summation of the number of neutrons and number of protons equals the mass number of an atom (denoted as’ MM ’). Thus, the number of neutrons = MZM - Z .

Complete Step By Step Answer:
In the given question, we have to find out the number of electrons in Mg2+M{g^{2 + }} ion. First of all, find out the atomic number of Magnesium from the periodic table which is equal to 12.
As atomic number is equal to the number of protons thus:
number of protons=12number{\text{ }}of{\text{ }}protons = 12
In case of neutral atom, number of electrons is equal to the number of protons so:
number of electrons=12number{\text{ }}of{\text{ electr}}ons = 12
Now, in case of Mg2+M{g^{2 + }} , it indicates that the magnesium atom might have lost 2 electrons to become a cation i.e. Mg2+M{g^{2 + }} . In this case:
number of electrons=122=10number{\text{ }}of{\text{ electr}}ons = 12 - 2 = 10
Alternatively, we can write the electronic configuration of MgMg . This will be 1s22s22p63s21{s^2}2{s^2}2{p^6}3{s^2}
We know that superscripts indicate the number of electrons occupied in each orbital, so summation of all superscripts tell us the total number of electrons which is equal to 12 i.e. 2+2+6+2=122 + 2 + 6 + 2 = 12 .
For Mg2+M{g^{2 + }} it will be 122=10  12 - 2 = 10\; electrons.

Note :
Each atom of a given element has the similar number of protons while atoms of distinct elements possess distinct numbers of protons. An atom consists of the same number of protons as well as electrons. As protons as well as electrons possess equal and opposite electrical charges, atoms have no overall electrical charge (i.e. neutral).