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Question

Question: What is the time-period of a tuning fork which has a number \(200\) marked on it? \(\begin{aligned...

What is the time-period of a tuning fork which has a number 200200 marked on it?
A.0.005s B.0.05s C.0.5s D.5s \begin{aligned} & A.0.005s \\\ & B.0.05s \\\ & C.0.5s \\\ & D.5s \\\ \end{aligned}

Explanation

Solution

The markings on the tuning fork generally indicates the frequency of the tuning fork. Frequency is the reciprocal of the time period of the oscillations produced by the tuning fork. Using this way we can solve this question.

Complete answer:
Generally the markings on the tuning fork indicates the frequency of the oscillation made by the tuning fork. Therefore 200200 marked on the tuning fork will be representing that it is the frequency of the tuning fork.
The frequency which is abbreviated as ff of a wave is defined as the number of full wave forms produced per second. This will be equivalent as the number of repetitions per second taking place or the number of oscillations per second happening.
Time Period (T) is defined as the time taken for one wave to complete its one full oscillation. Otherwise we can say that the number of seconds per waveform, or the number of seconds per oscillation. From this we can estimate that the frequency and time period are reciprocals. That is,
T=1fT=\dfrac{1}{f}
Here it is already mentioned that the frequency of the vibration of the tuning fork is,
f=200Hzf=200Hz
Substituting this value in the above equation will give,
T=1f=1200=0.005sT=\dfrac{1}{f}=\dfrac{1}{200}=0.005s
Therefore the time period of the tuning fork will be,
T=0.005sT=0.005s

So, the correct answer is “Option A”.

Note:
A tuning fork is very helpful and as well as useful for illustrating how a vibrating object can produce sound. The fork will have a handle and two tines. If the tuning fork is collided with a rubber hammer, the twines start to vibrate. The back and forth vibration of the twines creates disturbances of surrounding air molecules.