Question

What is the third term in a sequence of numbers that leave remainders of 1, 2 and 3 when divided by 2, 3 and 4 respectively?

• A. 11
• B. 17
• C. 19
• D. 35

Answer 1

Answer: (D)

35

Answer 2

L.C.M. (2,3,4) = 12
Number of the form that leave remainders of 1, 2 and 3 when divided by 2, 3 and 4 respectively =$12x−1$
Therefore,$(2−1)=(3−2)=(4−3)=1$, where $x$ is a natural number
Thus, the third number =$12(3)−1=35$
The correct answer is (D): 35