Question

What is the test to distinguish between $ZnS{O_4}$ and $ZnC{l_2}$?

Answer 1

Zinc sulfate is an inorganic compound. It is used as a supplement to treat zinc deficiency and to prevent the condition in those at high risk. Zinc chloride and its hydrates are chemical compounds. Zinc chlorides, which come in nine different crystalline shapes, are colorless or white and highly soluble in water.

Complete answer:
1. When we add $BaC{l_2}$ to the zinc sulfate solution, the following reaction occurs
$ZnS{O_4} + BaC{l_2} \to BaS{O_4} \downarrow + ZnC{l_2}$
Here $BaS{O_4}$ is the white precipitate.
2. When we add $BaC{l_2}$ to the zinc chloride solution, the following reaction occurs
$ZnC{l_2} + BaC{l_2} \to$ No visual effect
That is, here white precipitate is not formed.
So by adding $BaC{l_2}$ to each of the solutions helps to distinguish between $ZnS{O_4}$ and $ZnC{l_2}$.

Additional information:
Zinc sulphate and zinc chloride are used in a variety of applications on a small scale. In agriculture, the former is used as a weed killer and to defend against pests. It is also a key ingredient in the viscose rayon manufacturing process precipitating bath. It is one of the most popular barium salts that are water soluble. It is white, acidic, and gives a flame a yellow-green tint, much like most other barium salts.

Note:
It is important that we remember that when $BaC{l_2}$ is added to the $ZnS{O_4}$ and $ZnC{l_2}$, $ZnS{O_4}$ gives a white precipitate while $ZnC{l_2}$ does not give precipitate. Keep in mind that the aqueous solution gives a white precipitate with barium chloride solution. The precipitate is not soluble in mineral acids.