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Question

Chemistry Question on States of matter

What is the temperature at which the kinetic energy of 0.30.3 moles of helium is equal to the kinetic energy of 0.40.4 moles of argon -at 400K400\, K ?

A

400 K

B

873 K

C

533 K

D

300 K

Answer

533 K

Explanation

Solution

Number of moles of helium =0.3=0.3
Number of moles of argon =0.4=0.4
We know that KE=nRTKE = nRT
KEKE of helium =0.3×R×T=0.3 \times R \times T \ldots (i)
KEKE of argon =0.4×R×400=0.4 \times R \times 400 \ldots (ii)
According to question
KEKE of helium =KE= KE of argon
0.3×R×T=0.4×R×4000.3 \times R \times T=0.4 \times R \times 400
T=533KT=533\, K