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Question: What is the sum of the arithmetic sequence, \(2,9,14,19.........\) if there are \(38\) terms?...

What is the sum of the arithmetic sequence, 2,9,14,19.........2,9,14,19......... if there are 3838 terms?

Explanation

Solution

If we look at this sequence we can see that it increases with a constant value meaning that it is on arithmetic sequences. 9(+5),14(+5),199\left( { + 5} \right),14\left( { + 5} \right),19…..If we add 55 to 1919 the answer will be 2424, which is the next number in the sequence. If we wanted to work out of 3838 the number in the sequence we would need to work out the nn term of this sequence.
Formula used:
The sum of an arithmetic sequence,
xn=a+(n1)d{x_n} = a + \left( {n - 1} \right)d is given by
n=038=n2(2a+(n1)d)\sum\limits_{n = 0}^{38} {} = \dfrac{n}{2}\left( {2a + \left( {n - 1} \right)d} \right)
difference=2ndterm1stterm=3rdterm2ndterm\text{difference} = {2^{nd}}\text{term} - {1^{st}}\text{term} = {3^{rd}}\text{term} - {2^{nd}}\text{term}

Complete step-by-step solution:
The given arithmetic sequence is 9,14,19.......9,14,19.......
There are 3838 terms in the arithmetic sequence.
We have to use the formula of the
The sum of an arithmetic sequence,
xn=a+(n1)d{x_n} = a + \left( {n - 1} \right)d
n=038=n2(2a+(n1)d)\sum\limits_{n = 0}^{38} {} = \dfrac{n}{2}\left( {2a + \left( {n - 1} \right)d} \right)
Here aa is the first term
dd is the difference between each term. There are totally 3838 terms.
Here first term aa =9 = 9
Difference d=149=1914=5d = 14 - 9 = 19 - 14 = 5
d=5d = 5
Total number of terms n=38n = 38
Substitute the values in the equation we have,
n038=n2(2a+(n1)d)\sum\limits_{n - 0}^{38} {} = \dfrac{n}{2}\left( {2a + \left( {n - 1} \right)d} \right)
=382[2(9)+(381)5]= \dfrac{{38}}{2}\left[ {2\left( 9 \right) + \left( {38 - 1} \right)5} \right]
=382[18+(37)(5)]= \dfrac{{38}}{2}\left[ {18 + \left( {37} \right)\left( 5 \right)} \right]
Add the value, we get,
=19(18+185)= 19\left( {18 + 185} \right)
=19×203= 19 \times 203
=3857= 3857
Therefore the sum of the arithmetic sequence is 38573857

Note: In the arithmetic sequence it increases with a constant value and has a common difference. Common difference is the proper way and easy way to solve the question.
Additional information:
An Arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is called constant. For instance, the sequence 5,,7,9,11,13,15,........5,,7,9,11,13,15,........ is an arithmetic progression with a common difference of 22.
A finite portion of an arithmetic progression is called a finite arithmetic progression and sometimes just called an arithmetic progression. The sum of a finite arithmetic progression is called an arithmetic series.