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Question: What is the strongest base? A.Pyrrole B.Aniline C.Pyridine D. ![](https://www.vedantu.co...

What is the strongest base?
A.Pyrrole
B.Aniline
C.Pyridine
D.

Explanation

Solution

We have to know that the basicity of heterocyclic amine differs over a wide range and reflects on both the hybridization of nitrogen orbital consisting of the lone pair of electrons and affects the delocalization.

Complete step by step answer:

We have to know that the order of basicity is,
sp3(N) > sp2(N) > sp(N){\text{s}}{{\text{p}}^{\text{3}}}\left( {\text{N}} \right){\text{ > s}}{{\text{p}}^{\text{2}}}\left( {\text{N}} \right){\text{ > sp}}\left( {\text{N}} \right)
Pyrrole is a weak base. The lone pair of electrons of the nitrogen atoms interacts with four electrons of the two C = C{\text{C = C}} bonds to produce an aromatic six \pi{\text{\pi }} electron system same to that of benzene.
Therefore, the option (A) is incorrect.
Pyridine is a substantially weaker base than alkylamines like piperidine. The electron pair of pyridine takes place sp2{\text{s}}{{\text{p}}^{\text{2}}}-hybridized orbital and lies closer to the nucleus than the electron pair in the sp3{\text{s}}{{\text{p}}^{\text{3}}}-hybridized orbital of alkylamines. Pyridine is a weaker base.
Therefore, the option (B) is incorrect.
In aniline, the lone pair of electrons present in nitrogen could interact with the pi-system of the aromatic ring and this makes them less unused for donation.
Therefore, the option (C) is incorrect.
Structure (D) is piperidine.
Aliphatic amines are more bases than aromatic amines due to non-delocalized of lone pairs of nitrogen. The lone pair is piperidine sp3{\text{s}}{{\text{p}}^{\text{3}}}-hybridized orbital and there is no resonance (no pi system). Piperidine is more basic than others.
Therefore, the option (D) is correct.
The basicity of the given molecule is listed below as,
The pKa{\text{p}}{{\text{K}}_{\text{a}}} of piperidine is 11.2.
The pKa{\text{p}}{{\text{K}}_{\text{a}}} of pyridine is 5.2.
The pKa{\text{p}}{{\text{K}}_{\text{a}}} of aniline is 5.2.
The pKa{\text{p}}{{\text{K}}_{\text{a}}} of pyrrole is 4.
Therefore, the option D is correct.

Note:
We can use pyridine as a flavoring agent. The pyridine ring is a segment of two B vitamins namely niacin and pyridoxine. Niacin is otherwise called as nicotinic acid and is found in most organisms. Heterocyclic amines are carcinogens and are also known as HCA.