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Question: What is the standard deviation of \[\sigma (X) = \dfrac{{\sigma (Y)}}{2}\], what is \[\sigma (X - Y)...

What is the standard deviation of σ(X)=σ(Y)2\sigma (X) = \dfrac{{\sigma (Y)}}{2}, what is σ(XY)\sigma (X - Y)?

Explanation

Solution

Standard deviation is a measure of the amount of variation or dispersion of a set of values. A low standard deviation indicates that the values tend to be close to the mean of the set, while a high standard deviation indicates that the values are spread out over a wider range.

Complete step by step solution:
The Standard Deviation is a measure of how spread-out numbers are. Its symbol is σ\sigma (the Greek letter sigma). The formula is easy: it is the square root of the Variance i.e.
i=1n(XiXˉ)2\sqrt {\sum\limits_{i = 1}^n {{{({X_i} - \bar X)}^2}} }
Here Xˉ\bar X is the expected value of the data set and XX is the actual value of the dataset.
In the given case we are provided with a continuous function. A continuous function is a real-valued function whose graph does not have any breaks or holes. It is fully defined at a single point.
σ(XY)\sigma (X - Y) is the sum of the differences between an expected response XX from a model and the actual data YYfrom the range of data collected. It is used in the calculation of variance and standard deviations.
The standard deviation of a defined continuous function is zero because by its definition each XX data point corresponds exactly to each YY data point. Due to such correspondence, there will be no deviation to calculate.

Hence, we can conclude that the standard deviation of the given question is σ(XY)=0\sigma (X - Y) = 0.

Note:

Here it is assumed that YY is referring to the actual data.
Standard deviation may be abbreviated SD
Standard deviation should be carefully analysed before reaching a conclusion. Variance cannot be negative but standard deviation can be negative.