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Question: What is the shorthand electronic configuration of Pt?...

What is the shorthand electronic configuration of Pt?

Explanation

Solution

Hint : Pt is the symbol of the element Platinum of the periodic table. Its atomic number is 7878. Platinum belongs to the platinum group of elements, which is part of the periodic table's group 1010. It has six isotopes that exist naturally. It is the element of d-block.

Complete Step By Step Answer:
The electron configuration in shorthand begins with the symbol of the noble gas from the previous time, followed by the additional electron configuration for the given part.
For ex – Since, we know that the atomic number of sodium is 1010, so sodium has one more 3s3s electron than the noble gas neon, its shorthand notation is [Ne]3s[Ne]3s.
Electronic configuration of any element is done on the basis of Aufbau principle. It states that the lowest energy orbitals are occupied first, followed by the higher energy orbitals.
Since, there are 7878 electrons in the platinum element, then all these electrons will be in the atomic orbital in the following order - 1s,2s,2p,3s,3p,4s,3d,4p,5s,4p,5d,6p,7s,.....1s,2s,2p,3s,3p,4s,3d,4p,5s,4p,5d,6p,7s,.....
Here, the maximum number of electrons which can be filled in the following orbitals are listed below

OrbitalMaximum number of electrons
s22
p88
d1818
f3232

According to the rule, firstly 22 electrons of platinum will be filled in 1s1s orbital, then next 2 electrons will be filled in 2s2s orbital and so on.
Like this, after filling the electrons in the orbitals, the electronic configuration of platinum is [Xe]4f145d96s1\left[ {{\mathbf{Xe}}} \right]{\mathbf{4}}{{\mathbf{f}}^{14}}{\mathbf{5}}{{\mathbf{d}}^9}{\mathbf{6}}{{\mathbf{s}}^1}.

Note :
The real answer is [Xe]4f145d86s2[Xe]4{f^{14}}5{d^8}6{s^2} but due to exception in platinum, the answer is given above. This is because the rule of thumb is applied here which means that half-filled orbitals are more stable.