Question
Question: What is the resistance of a wire if its radius is doubled? (A) Becomes twice (B) Becomes one-fou...
What is the resistance of a wire if its radius is doubled?
(A) Becomes twice
(B) Becomes one-fourth
(C) Becomes four times
(D) Becomes one-half
Solution
We are asked to find the change in resistance of the wire when one of its parameters is changed. Thus, we will first find the relation of resistance with the parameters of wire.
Formula used
R=ρAL
Where, R is the resistance of the wire, ρ is the resistivity of the material of wire, L is the length of the wire and A is the cross sectional area of the wire.
Step By Step Solution
Firstly,
When the length L of a wire is increased, the atoms of the wire increases and thus the resistance R also increases.
Thus, resistance is directly proportional to the length of the wire.
R∝L
Now,
When the cross sectional area of the wire is increased, the atoms get sparsely separated thus increasing the free space for the charge to flow and in turn decreasing the resistance.
Thus, resistance is inversely proportional to the cross sectional area of the wire.
R∝A1
Then,
Combining both the proportionalities, we get
R∝AL
To remove the proportionality symbol, we introduce a proportionality constant
R=ρAL
Here, ρ is the proportionality constant known as resistivity. Resistivity is the property of a material which refers to the capacity of a material to oppose the flow of a charge.
Now,
According to the question, the radius of the wire is doubled.
Firstly,
The original resistance was,
R=ρπr2L⋅⋅⋅⋅(1)
After the increase, the resistance becomes,
RNew=ρπ(2r)2L⇒RNew=41ρπr2L
Now,
Putting in equation (1) , we get
RNew=41R
Thus, the answer is (B).
Note: We found the answer to be one-fourth as per this particular situation. But if the situation was to double the length, then the new resistance becomes four times of the original resistance.