Question: What is the relative error in g calculated from $T = 2\pi\sqrt{\mathcal{l}/g}$? Given relative err...

Question

What is the relative error in g calculated from $T = 2\pi\sqrt{\mathcal{l}/g}$ ? Given relative errors in T and l are ± x and ± y respectively-

Answer 1

T² = 4p² $\frac{\mathcal{l}}{g}$ Ž g = $\frac{4\pi^{2}\mathcal{l}}{T^{2}}$

$\frac{\Delta g}{g}$ × 100 = $\frac{\Delta\mathcal{l}}{\mathcal{l}}$ × 100 + 2 $\frac{\Delta T}{T}$ × 100

Question: What is the relative error in g calculated from \(T = 2\pi\sqrt{\mathcal{l}/g}\)? Given relative err...