Question

What is the relationship between electric field intensity $E$, current density $J$ and specific resistance $\rho$ ?

• A. $J=\frac{1}{\rho} E$
• B. $J=\rho E$
• C. $E=\frac{\rho}{J}$
• D. $\rho=JE$

Answer 1

Answer: (A)

$J=\frac{1}{\rho} E$

Answer 2

According to electron theory of metals for a conductor resistivity $\rho$ in terms of electric field E and current density J is $\rho=\frac{E}{J}$ or $J=\frac{1}{\rho} E$